A) Moves with one-fourth energy as that of the initial energy
B) Moves with one-fourth of momentum as that of the initial momentum
C) Will be half in number
D) Will be one-fourth in number
Correct Answer: D
Solution :
Number of ejected electrons\[\propto \text{(Intensity)}\propto \frac{1}{{{(\text{Distance})}^{2}}}\] Therefore an increment of distance two times will reduce the number of ejected electrons to \[\frac{1}{4}th\]of the previous one.
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