A) 2 V
B) Less than 2 V
C) Zero
D) Greater than 2 V
Correct Answer: D
Solution :
According to Einstein's photoelectric equation \[E={{W}_{0}}+{{K}_{\max }}\] \[\Rightarrow \,\,{{V}_{0}}=\frac{hc}{e}\,\left[ \frac{1}{\lambda }-\frac{1}{{{\lambda }_{0}}} \right]\] Hence if l decreases \[{{V}_{0}}\] increases.
You need to login to perform this action.
You will be redirected in
3 sec
