A) \[2.1\times {{10}^{-19}}J\]
B) \[8.5\times {{10}^{-19}}J\]
C) \[5.3\times {{10}^{-19}}J\]
D) \[3.2\times {{10}^{-19}}J\] \[(h=6.63\times {{10}^{-34}}Js)\]
Correct Answer: A
Solution :
\[{{K}_{\max }}=h\nu -{{W}_{0}}\]\[=6.6\times {{10}^{-34}}\times 8\times {{10}^{14}}-3.2\times {{10}^{-19}}\] \[=2.1\times {{10}^{-19}}J\]
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