A) 12.4 eV
B) 6.2 eV
C) 100 eV
D) 200 eV
Correct Answer: B
Solution :
\[{{K}_{\max }}\,(eV)=12375\,\left[ \frac{1}{\lambda \,({\AA})}-\frac{1}{{{\lambda }_{0}}({\AA})} \right]\] \[=12375\,\left[ \frac{1}{1000}-\frac{1}{2000} \right]\] \[=6.2\,eV\]
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