A) \[5.9\times {{10}^{14}}\]cycle/sec
B) \[6.5\times {{10}^{14}}cycle/\sec \]cycle/sec
C) \[9.4\times {{10}^{14}}cycle/\sec \]cycle/sec
D) \[6.08\times {{10}^{14}}\] cycle/sec
Correct Answer: D
Solution :
\[{{W}_{0}}=h{{\nu }_{0}}\,\Rightarrow \,\,{{\nu }_{0}}=\frac{{{W}_{0}}}{h}=\frac{2.51\times 1.6\times {{10}^{-19}}}{6.6\times {{10}^{-34}}}\] \[=6.08\times {{10}^{14}}\,Cycle/\sec .\]
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