A) Stopping potential will decrease
B) Stopping potential will increase
C) Kinetic energy of emitted electrons will decrease
D) The value of work function will decrease
Correct Answer: B
Solution :
Stopping potential \[{{V}_{0}}=\frac{hc}{e}\left[ \frac{1}{\lambda }-\frac{1}{{{\lambda }_{0}}} \right]\]. As \[\lambda \] decreases so \[{{V}_{0}}\] increases.
You need to login to perform this action.
You will be redirected in
3 sec
