A) 4125 Å
B) 2062.5 Å
C) 3000 Å
D) 6000 Å
Correct Answer: C
Solution :
\[W.\,(eV)=\frac{12375}{{{\lambda }_{0}}({\AA})}\Rightarrow {{\lambda }_{0}}=\frac{12375}{4.125}=3000{\AA}\]
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