A) Double the earlier value
B) Unchanged
C) More than doubled
D) Less than doubled
Correct Answer: C
Solution :
\[E={{W}_{0}}+{{K}_{\max }}\Rightarrow {{K}_{\max }}=E-{{W}_{0}}=h\nu -{{W}_{0}}\] \[\Rightarrow {{K}_{1}}=h\nu -{{W}_{0}}\] and \[{{K}_{2}}=2h\nu -{{W}_{0}}\] \[\Rightarrow {{K}_{2}}>2{{K}_{1}}\]
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