A) None of these
B) A only
C) A and B only
D) All the three metals
Correct Answer: C
Solution :
Energy of incident radiations (in eV) \[=\frac{12375}{4100}=3.01\,eV\] Work function of metal A and B are less then \[3.01eV\], so A and B will emit photo electrons.You need to login to perform this action.
You will be redirected in
3 sec