A) 15 J
B) \[16\times {{10}^{-14}}J\]
C) \[4\times {{10}^{-19}}J\]
D) \[4\times {{10}^{-81}}J\]
Correct Answer: C
Solution :
\[{{W}_{0}}=\frac{hc}{{{\lambda }_{0}}}=\frac{6.625\times {{10}^{-34}}\times 3\times {{10}^{8}}}{5000\times {{10}^{-10}}}J=4\times {{10}^{-19}}J\]
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