A) \[1.5\times {{10}^{29}}\]
B) \[1.5\times {{10}^{31}}\]
C) \[1.5\times {{10}^{33}}\]
D) \[1.5\times {{10}^{35}}\]
Correct Answer: B
Solution :
\[P=\frac{W}{t}=\frac{nhc}{\lambda t}\,\Rightarrow \,\,\left( \frac{n}{t} \right)=\frac{P\lambda }{hc}\]\[=\frac{10\times {{10}^{3}}\times 300}{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}\] \[=1.5\times {{10}^{31}}\]
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