A) 10 min
B) 12 min
C) 15 min
D) 20 min
Correct Answer: D
Solution :
[d] Part of the tank filled by both in 10 min \[=10\times \left( \frac{1}{20}+\frac{1}{60} \right)=\frac{40}{60}=\frac{2}{3}\] Remaining part\[=\left( 1-\frac{2}{3} \right)=\frac{1}{3}\] \[\frac{1}{3}\]part is now filled in \[\left( \frac{60\times 1}{3} \right)\min .\] \[=20\min \] |
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