A) 3 h 15 min
B) 3 h 45 min
C) 4 h
D) 4 h 15 min
Correct Answer: B
Solution :
[b] Time taken by the tap to make the tank half-full = 3 h Remaining part\[=\frac{1}{2}\] Part filled by 4 taps in 1 h \[=\left( 4\times \frac{1}{6} \right)=\frac{2}{3}\] \[\frac{2}{3}\] part is filled in 1 h. \[\frac{1}{2}\] part is filled in\[\left( \frac{3}{2}\times \frac{1}{2} \right)\,h\] \[=\frac{3}{4}\,h=45\min \] Required time \[=3\,h\,\,45\min \] |
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