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SSC Quantitative Aptitude Pipes & Cisterns Question Bank Pipe and Cistern (I)

  • question_answer
    A tank can be filled by a tap in 20 min and by another tap in 60 min. Both the taps are kept open for 10 min and then the first tap in shut off. After this, the tank will be completely filled in

    A) 10 min

    B) 12 min

    C) 15 min

    D) 20 min

    Correct Answer: D

    Solution :

    [d] Part of the tank filled by both in 10 min \[=10\times \left( \frac{1}{20}+\frac{1}{60} \right)=\frac{40}{60}=\frac{2}{3}\] Remaining part\[=\left( 1-\frac{2}{3} \right)=\frac{1}{3}\] \[\frac{1}{3}\]part is now filled in \[\left( \frac{60\times 1}{3} \right)\min .\] \[=20\min \]


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