A) \[\frac{\pi }{3}\]
B) \[\frac{\pi }{2}\]
C) \[\frac{\pi }{6}\]
D) None of these
Correct Answer: B
Solution :
\[\theta ={{\cos }^{-1}}\left[ \frac{6+4-10}{\sqrt{50}\sqrt{9}} \right]={{\cos }^{-1}}(0)=\frac{\pi }{2}\].
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