JEE Main & Advanced Mathematics Three Dimensional Geometry Question Bank Plane

  • question_answer
    The equation of the plane which is parallel to the plane \[x-2y+2z=5\] and whose distance from the point \[(1,\,2,\,3)\] is 1, is

    A)            \[x-2y+2z=3\]

    B)            \[x-2y+2z+3=0\]

    C)            \[x-2y+2z=6\]

    D)            \[x-2y+2z+6=0\]

    Correct Answer: C

    Solution :

               Equation of plane parallel to \[x-2y+2z=5\] is \[x-2y+2z+k=0\]                         ?..(i) Now, according to question, \[\frac{1-4+6+k}{\sqrt{9}}=\pm 1\]            or \[k+3=\pm \,3\,\,\Rightarrow \,\,k=0\] or ? 6            \[\therefore \,\,x-2y+2z-6=0\] or \[x-2y+2z=6\].

You need to login to perform this action.
You will be redirected in 3 sec spinner