A) \[28x-17y+9z=0\]
B) \[28x+17y+9z=0\]
C) \[28x-17y+9x=0\]
D) \[7x-3y+z=0\]
Correct Answer: A
Solution :
Equation of plane containing the line of intersection of planes is, \[(2x-y)+\lambda \,(y-3z)=0\] ??(i) Also, plane (i) is perpendicular to \[4x+5y-3z-8=0\] \[\therefore \,\,4\,(2)+5\,(\lambda -1)-3\,(-3\lambda )=0\] \[\Rightarrow \,\,14\lambda =-\,3\,\,\Rightarrow \,\,\lambda =-\frac{3}{14}\] Put the value of \[\lambda \] in (i), we get \[28x-17y+9z=0\], which is the required plane.
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