A) A line
B) A plane whose normal is equally inclined to axes
C) A plane which passes through the origin
D) A sphere
Correct Answer: B
Solution :
According to question, \[{{(x-3)}^{2}}+{{(y-4)}^{2}}+{{(z+2)}^{2}}={{(x-2)}^{2}}+{{(y-3)}^{2}}+{{(z+3)}^{2}}\] \[\therefore \] The equation reduces to a plane as 2nd degree terms cancel out. The equation is \[2x+2y+2z=7,\] hence equally inclined to axes.
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