A) \[a(x-a)-b(y-b)-c(z-c)=0\]
B) \[a(x+a)+b(y+b)+c(z+c)=0\]
C) \[a(x-a)+b(y-b)+c(z-c)=0\]
D) None of these
Correct Answer: C
Solution :
Normal will be OA whose direction ratios are \[a-0,\] \[b-0,\] \[c-0\] i.e., a, b, c. It passes through \[A\,(a,\,\,b,\,\,c).\] \[\therefore \] Equation of required plane is, \[a\,(x-a)+b\,(y-b)+c\,(z-c)=0\].You need to login to perform this action.
You will be redirected in
3 sec