A) \[2x+3y+4z=4\]
B) \[2x+3y+4z+4=0\]
C) \[2x-3y+4z+4=0\]
D) \[2x+3y-4z+4=0\]
Correct Answer: D
Solution :
Plane parallel to the plane \[2x+3y-4z=0\] is \[2x+3y-4z+k=0\] .....(i) Also plane (i) is passing through (1, 2, 3) \[\therefore \] \[(2)\,(1)+(3)(2)-(4)(3)+k=0\Rightarrow k=4\] \[\therefore \] Required plane is \[2x+3y-4z+4=0\].You need to login to perform this action.
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