A) \[3x-4z+1=0\]
B) \[3x-4y+1=0\]
C) \[3x+4y+1=0\]
D) None of these
Correct Answer: A
Solution :
Plane passing through (1, 1, 1) is \[a\,(x-1)+b\,(y-1)+c\,(z-1)=0\] It also passes through (1, ? 1, 1) and (?7, ? 3, ? 5), then \[b=0,\,\,a=-\frac{3}{4}c\] Hence the required equation is \[3x-4z+1=0\]. Trick : Since the plane \[3x-4z+1=0\] passes through given three points.You need to login to perform this action.
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