A) \[(3a,3b,3c)\]
B) \[\left( \frac{a}{3},\frac{b}{3},\frac{c}{3} \right)\]
C) \[\left( \frac{3}{a},\frac{3}{b},\frac{3}{c} \right)\]
D) \[\left( \frac{1}{3a},\frac{1}{3b},\frac{1}{3c} \right)\]
Correct Answer: D
Solution :
Centroid is \[\left( \frac{\frac{1}{a}+0+0}{3},\frac{0+\frac{1}{b}+0}{3},\frac{0+0+\frac{1}{c}}{3} \right)\] i.e.,\[\,\left( \frac{1}{3a},\frac{1}{3b},\frac{1}{3c} \right)\].
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