A) \[x+y+z=0\]
B) \[x+y+z=1\]
C) \[x+y-z=1\]
D) \[\frac{x}{a}+\frac{y}{a}+\frac{z}{a}=1\]
Correct Answer: B
Solution :
Equation of required plane is, \[\frac{x}{1}+\frac{y}{1}+\frac{z}{1}=1\] \[\Rightarrow \,x+y+z=1\].
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