JEE Main & Advanced Mathematics Three Dimensional Geometry Question Bank Plane

  • question_answer
    If the length of perpendicular drawn from origin on a plane is 7 units and its direction ratios are ?3, 2, 6, then that plane is [MP PET 1998]

    A)            \[-3x+2y+6z-7=0\]

    B)            \[-3x+2y+6z-49=0\]

    C)            \[3x-2y+6z+7=0\]

    D)            \[-3x+2y-6z-49=0\]

    Correct Answer: B

    Solution :

               Equation of a plane, when direction ratio and length of perpendicular is given, \[ax+by+cz=p\,\,\sqrt{{{a}^{2}}+{{b}^{2}}+{{c}^{2}}}\]            Given, \[(a,\,\,b,\,\,c)\,\,\to \,\,(-\,3,\,\,2,\,\,6)\]            \[-\,3x+2y+6z=7\,\sqrt{{{(-\,3)}^{2}}+{{2}^{2}}+{{6}^{2}}}\]            \[-\,3x+2y+6z=49\].

You need to login to perform this action.
You will be redirected in 3 sec spinner