A) 15, ?5, 3
B) 1, ?5, 3
C) ?15, 5, ?3
D) 1, ?6, 20
Correct Answer: A
Solution :
If plane \[x-3y+5z=d\] passes through point (1, 2, 4). Then \[1-6+20=d\,\,\Rightarrow \,\,d=15\] \[\therefore \,\,\]Plane, \[x-3y+5z=15\]\[\Rightarrow \,\,\frac{x}{15}+\frac{y}{-5}+\frac{z}{3}=1\] Hence length of intercept cut by it on the axes (x, y, z) are respectively (15, ? 5, 3).
You need to login to perform this action.
You will be redirected in
3 sec
