JEE Main & Advanced Mathematics Three Dimensional Geometry Question Bank Plane

  • question_answer
    The distance of the plane \[6x-3y+2z-14=0\]from the origin is [MP PET 2003]

    A)            2

    B)            1

    C)            14

    D)            8

    Correct Answer: A

    Solution :

               Distance of plane from origin                                               = \[\frac{d}{\sqrt{{{a}^{2}}+{{b}^{2}}+{{c}^{2}}}}\] \[=\frac{14}{\sqrt{{{6}^{2}}+{{3}^{2}}+{{2}^{2}}}}=\frac{14}{\sqrt{49}}=\frac{14}{7}=2\].

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