JEE Main & Advanced Mathematics Three Dimensional Geometry Question Bank Plane

  • question_answer
    The angle between two planes \[x+2y+2z=3\] and \[-5x+3y+4z=9\] is [MP PET 2004]

    A)            \[{{\cos }^{-1}}\frac{3\sqrt{2}}{10}\]

    B)            \[{{\cos }^{-1}}\frac{19\sqrt{2}}{30}\]

    C)            \[{{\cos }^{-1}}\frac{9\sqrt{2}}{20}\]

    D)            \[{{\cos }^{-1}}\frac{3\sqrt{2}}{5}\]

    Correct Answer: A

    Solution :

               Angle between two planes is, \[\cos \theta =\frac{{{a}_{1}}{{a}_{2}}+{{b}_{1}}{{b}_{2}}+{{c}_{1}}{{c}_{2}}}{\sqrt{a_{1}^{2}+b_{1}^{2}+c_{1}^{2}}\,\sqrt{a_{2}^{2}+b_{2}^{2}+c_{2}^{2}}}\]                    \[\cos \theta =\frac{(1)\,(-5)\,+(2)\,(3)+(2)\,(4)}{\sqrt{{{1}^{2}}+{{2}^{2}}+{{2}^{2}}}\sqrt{{{(-5)}^{2}}+{{3}^{2}}+{{4}^{2}}}}\]                    \[\cos \theta =\frac{3\sqrt{2}}{10}\Rightarrow \theta ={{\cos }^{-1}}\left( \frac{3\sqrt{2}}{10} \right)\].


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