A) \[3x-4y+18z+32=0\]
B) \[3x+4y-18z+32=0\]
C) \[4x+3y-17z+31=0\]
D) \[4x-3y+z+1=0\]
Correct Answer: D
Solution :
Equation of any plane passing through (0, 1, 2) is \[a(x-0)+b(y-1)+c(z-2)=0\] ......(i) Plane (i) passes through (?1, 0, 3), then \[a(-1-0)+b(0-1)+c(3-2)=0\] Þ \[-a-b+c=0\]Þ \[a+b-c=0\] .....(ii) Plane (i) is perpendicular to the plane \[2x+3y+z=5\], then \[2a+3b+c=0\] ......(iii) Solving (ii) and (iii), we get \[a=-4k,b=3k,c=-k\] Putting these values in (i), \[-4k(x)+3k(y-1)-k(z-2)=0\] Þ \[-4x+3y-3-z+2=0\] Þ \[-4x+3y-z-1=0\] Þ \[4x-3y+z+1=0\].
You need to login to perform this action.
You will be redirected in
3 sec
