A) 1
B) 3
C) 0
D) infinite
Correct Answer: B
Solution :
We have AABAA is divisible by 33. So, it is divisible by both 3 and 11. \[\therefore \text{A + B + A - (A + A)=B}\] is divisible by 11. \[\Rightarrow B=0\] Also, A+A+B+A+A=4A+B is divisible by 3. \[\Rightarrow 4A\] is divisible by 3 \[(\because B=0)\] \[\Rightarrow A\] is divisible by 3 Hence, possible values of A are 0, 3, 6, 9 But A can't be equal to zero. \[\therefore \] Number of possible 5-digit numbers are 3.You need to login to perform this action.
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