A) \[\left( 1,\frac{\sqrt{3}}{2} \right)\]
B) \[\left( \frac{2}{3},\frac{1}{\sqrt{3}} \right)\]
C) \[\left( \frac{2}{3},\frac{\sqrt{3}}{2} \right)\]
D) \[\left( 1,\frac{1}{\sqrt{3}} \right)\]
Correct Answer: D
Solution :
Clearly, the triangle is equilateral. So, the incentre is the same as the centroid. \[\therefore \] Incentre \[=\,\left( \frac{1+0+2}{3},\,\,\frac{\sqrt{3}+0+0}{3} \right)=\left( 1,\,\frac{1}{\sqrt{3}} \right)\].You need to login to perform this action.
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