A) 1
B) 1.5
C) 3
D) 4
Correct Answer: A
Solution :
\[D\,\,(3,\,\,2),\,\,E\,(3,\,\,4),\,\,F\,(2,\,\,3)\] Area\[=\frac{1}{2}\,\left| \,\begin{matrix} 3 & 2 & 1 \\ 3 & 4 & 1 \\ 2 & 3 & 1 \\ \end{matrix}\, \right|\]\[=\frac{1}{2}[3\,(4-3)-2(3-2)+1(9-8)]\] = 1 sq. units.You need to login to perform this action.
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