A) \[(11,\text{ }10)\]
B) \[(10,\text{ }11)\]
C) \[(11/2,\,5)\]
D) \[(5,\text{ }11/2)\]
Correct Answer: A
Solution :
\[{{(a-3)}^{2}}+{{(b-4)}^{2}}=100\] and \[\frac{b-7}{3}=\frac{a-7}{4}\] Hence (a, b)=(11, 10). Trick: Check with options. We find that the point (11, 10) satisfies both the conditions i.e. \[AC=\sqrt{{{(11-3)}^{2}}+{{(10-4)}^{2}}}=10\]. Also this is collinear with A, B.You need to login to perform this action.
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