A) 2, 3
B) 1, 0
C) 1, 2
D) 1, -1/2
E) (e) 0, 3
Correct Answer: E
Solution :
(e) If points \[(k,3),(2,k)\]and \[(-k,\,3)\] are collinear then, \[[k(k-3)+2(3-3)-k(3-k)]=0\] Þ \[[k(k-3)+0+k(k-3)=0\]Þ \[2k\,(k-3)=0\] Þ \[k=0,\,3\].You need to login to perform this action.
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