A) \[+\frac{50{}^\circ }{9}\]per mm
B) \[-\frac{50{}^\circ }{9}\]per mm
C) \[+\frac{9{}^\circ }{50}\]per mm
D) \[-\frac{9{}^\circ }{50}\]per mm
Correct Answer: B
Solution :
\[\theta =a+\frac{b}{{{\lambda }^{2}}}\] \[30=a+\frac{b}{{{(5000)}^{2}}}\] and \[50=a+\frac{b}{{{(4000)}^{2}}}\] Solving for a, we get \[a=-\frac{50{}^\circ }{9}\,per\,mm\]You need to login to perform this action.
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