A) 50%
B) 100%
C) 12.5%
D) 37.5%
Correct Answer: C
Solution :
Intensity of polarised light from first polarizer \[=\frac{100}{2}=50\] \[I=50{{\cos }^{2}}60{}^\circ =\frac{50}{4}=12.5\]You need to login to perform this action.
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