A) \[9,\,0\]
B) \[-3,-6\]
C) \[-9,0\]
D) \[8,-2\]
Correct Answer: D
Solution :
(d): \[\alpha ,\frac{1}{\alpha }\Rightarrow \alpha +\frac{1}{\alpha }=\frac{-9}{{{k}^{2}}-16}\] and \[1=\frac{6k}{{{k}^{2}}-16}\Rightarrow {{k}^{2}}-16-6k=0\]: Solve this quadraticYou need to login to perform this action.
You will be redirected in
3 sec