A) \[k=1\]
B) \[k=2\]
C) \[k=3\]
D) \[k=4\]
Correct Answer: D
Solution :
(d): \[p\left( 2 \right)=0~\,\,\,k{{\left( 2 \right)}^{4}}-13{{\left( 2 \right)}^{3}}+k{{\left( 2 \right)}^{2}}+12\times 2=0\] \[\Rightarrow 16k-104+4k+24=0\] \[\Rightarrow 20k=80\Rightarrow k=4\]You need to login to perform this action.
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