A) \[x-\frac{1}{x}\]
B) \[x+\frac{1}{x}-1\]
C) \[x+\frac{1}{x}\]
D) \[{{x}^{2}}+\frac{1}{{{x}^{2}}}\]
Correct Answer: C
Solution :
\[{{x}^{2}}+\frac{1}{{{x}^{2}}}+2-2x\frac{2}{x}\] \[=\left( x+\frac{1}{x} \right)\left( x+\frac{1}{x}-2 \right)\]You need to login to perform this action.
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