A) -109
B) -88
C) -84
D) -64
Correct Answer: A
Solution :
We have, \[\frac{{{a}^{2}}-19a-25}{a-7}=a-12+\frac{R}{a-7}\] \[\Rightarrow \]\[\frac{{{a}^{2}}-19a-25}{a-7}=\frac{(a-12)(a-7)+R}{a-7}\] \[\Rightarrow \]\[{{a}^{2}}-19a-25={{a}^{2}}-19a+84+R\] \[\Rightarrow \]\[-84-25=R\Rightarrow R=-109\]You need to login to perform this action.
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