A) -1, 3
B) 1,-3
C) 1,-2
D) -1,-2
Correct Answer: B
Solution :
Let,\[f(x)={{x}^{3}}-7x+6\]and \[g(x)=x-2\]M Now, by long division method, we have \[\therefore \]\[(x-2)({{x}^{2}}+2x-3)=0\] For other solutions, \[{{x}^{2}}+2x-3=0\] \[\Rightarrow \]\[{{x}^{2}}+3x-x-3=0\Rightarrow (x+3)(x-1)=0\] \[\Rightarrow \]\[x=-3\]or 1You need to login to perform this action.
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