A) -2,-6
B) 2,-6
C) -2, 6
D) 2, 6
Correct Answer: C
Solution :
Let \[f(x)={{x}^{3}}-2{{x}^{2}}+px-q\] and \[g(x)={{x}^{2}}-2x-3=(x-3)(x+1)\] Now, when \[g(x),\]leaves a remainder \[(x-6).\] Then, we have, \[f(3)=x-6\]and\[f(-1)=x-6\] \[\Rightarrow \]\[27-18+3p-q=3-6\] and \[-1-2-p-q=-1-6\] \[\Rightarrow \]\[3p-q=-12\] ?(i) and \[p+q=4\] Adding (i) and (ii), we get ?(ii) \[4p=-8\Rightarrow p=-2\] and \[q=3(-2)+12=-6+12=6\]You need to login to perform this action.
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