A) \[0\]
B) \[2\]
C) \[4\]
D) \[6\]
Correct Answer: B
Solution :
\[{{a}^{2}}+{{b}^{2}}+2ab+2bc+2ca+{{c}^{2}}-{{c}^{2}}\] \[={{(a+b+c)}^{2}}-{{c}^{2}}\] \[=(a+b)(a+b+2c)\] On comparing with \[(a+b+m)(a+b+nc),\] We get \[m=0\]and \[n=2.\] \[\Rightarrow \]\[m+n=0+2=2\]You need to login to perform this action.
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