A) \[1\]
B) \[-1\]
C) \[\frac{1}{2}\]
D) \[0\]
Correct Answer: D
Solution :
Given \[\frac{x}{y}+\frac{y}{x}=-1\Rightarrow \frac{{{x}^{2}}+{{y}^{2}}}{xy}=-1\] \[\Rightarrow \]\[{{x}^{2}}+{{y}^{2}}+xy=0\] ?..(i) \[{{x}^{3}}-{{y}^{3}}=(x+y)({{x}^{2}}+xy+{{y}^{2}})=0\]You need to login to perform this action.
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