A) \[x+7\]
B) \[x+9\]
C) \[x+4\]
D) \[~x+8\]
Correct Answer: C
Solution :
(c): \[\frac{{{x}^{3}}+9{{x}^{2}}+26x+24}{(x+2)(x+3)}=\frac{(x+2)(x+3)(x+4)}{(x+2)(x+3)}=(x+4)\] \[\therefore \,\,\text{3rd}\,\text{factor}=(x+4)\]You need to login to perform this action.
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