A) 0
B) 1
C) 2
D) 3
Correct Answer: D
Solution :
We have, \[a+b+c=0\] \[\therefore \]\[{{a}^{3}}+{{b}^{3}}+{{c}^{3}}=3abc\] ?(i) Now, \[\frac{{{a}^{2}}}{bc}+\frac{{{b}^{2}}}{ca}+\frac{{{c}^{2}}}{ab}=\frac{{{a}^{3}}+{{b}^{3}}+{{c}^{3}}}{abc}\] \[\frac{1}{abc}=(3abc)=3\] [Using (i)You need to login to perform this action.
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