9th Class Mathematics Polynomials Question Bank Polynomials

  • question_answer
    Area of a rectangular field is \[(2{{x}^{3}}-11{{x}^{2}}-4x+5)\,sq.\]units and side of a square field is (\[(2{{x}^{2}}+4)\]units. Find the difference between their areas (in sq. units).

    A) \[4{{x}^{4}}-2{{x}^{3}}-4x+11\]

    B) \[4{{x}^{4}}-2{{x}^{3}}+27{{x}^{2}}+4x+11\]

    C) \[4{{x}^{4}}+27{{x}^{2}}+4x-11\]

    D) \[4{{x}^{4}}+2{{x}^{3}}+27{{x}^{2}}+4x+11\]   

    Correct Answer: B

    Solution :

    Area of rectangular field \[=(2{{x}^{3}}-11{{x}^{2}}-4x+5)sq.\]units Side of square field \[=(2{{x}^{2}}+4)\]units \[\therefore \]Areal of square field \[={{(2{{x}^{2}}+4)}^{2}}\] \[=(4{{x}^{4}}+16+16{{x}^{2}})\,sq.\,\]units \[\therefore \]Required difference \[=4{{x}^{4}}+16+16{{x}^{2}}-2{{x}^{3}}+11{{x}^{2}}+4x-5\] \[=(4{{x}^{4}}-2{{x}^{3}}+27{{x}^{2}}+4x+11)\,sq.\]units


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