A) \[a=1\]
B) \[a=-1\]
C) \[a=2\]
D) \[a=-2\]
Correct Answer: B
Solution :
\[2{{(1)}^{3}}+a{{(1)}^{2}}+3(1)-5={{(1)}^{3}}+{{(1)}^{2}}-4(1)-a\] \[2+a+3-5=1+1-4-a\] \[\Rightarrow \]\[2a=-2\Rightarrow a=-1\]You need to login to perform this action.
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