A) 3
B) 2
C) 1
D) 0
Correct Answer: D
Solution :
It is given that \[a+b+c=3x.\]Then, \[{{(x-a)}^{3}}+{{(x-b)}^{3}}+{{(x-c)}^{3}}-3(x-a)(x-b)(x-c)\] \[=(x-a+x-b+x-c)[{{(x-a)}^{2}}+{{(x-b)}^{2}}\] \[+{{(x-c)}^{2}}-(x-a)(x-b)-(x-b)(x-c)\] \[-(x-c)(x-a)]=0\]You need to login to perform this action.
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