A) \[{{x}^{3}}-3{{x}^{2}}-8x-4\]
B) \[{{x}^{3}}+3{{x}^{2}}-8x-4\]
C) \[{{x}^{3}}+3{{x}^{2}}+8x-4\]
D) \[{{x}^{3}}-3{{x}^{2}}-8x+4\]
Correct Answer: C
Solution :
For a cubic polynomial, \[a{{x}^{3}}+b{{x}^{2}}+cx+d\] Sum of zeroes \[=-\frac{b}{a}\] Sum of the product of zeroes taken two at a time \[=\frac{c}{a}\] Product of zeroes \[=-\frac{d}{a}\] We have, \[-\frac{b}{a}=-3,\,\frac{c}{a}=8\] and \[\frac{-d}{a}=4\] \[\therefore \] \[{{x}^{3}}+3{{x}^{2}}+8x-4\] is the required polynomial.
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