A) 36.3 kW
B) 40.1 kW
C) 43.8 kW
D) 47.4 kW
Correct Answer: A
Solution :
For reaction turbine, \[{{v}_{f1}}={{v}_{f2}}={{v}_{f}}\] \[\sin {{\alpha }_{1}}=\frac{{{v}_{f}}}{236},\] \[\sin {{\beta }_{2}}=\frac{{{v}_{f}}}{232}\,\,\,\therefore \,\,\,{{\alpha }_{1}}={{\beta }_{2}}\] \[\sin {{\alpha }_{2}}=\frac{{{v}_{f}}}{126},\] \[\sin {{\beta }_{1}}=\frac{{{v}_{f}}}{132}\,\,\,\therefore \,\,\,{{\alpha }_{1}}={{\beta }_{2}}\] \[{{R}_{d}}=0.5\] Now \[{{R}_{d}}=\frac{v_{r2}^{2}-{{v}^{2}}}{2u\,({{v}_{\omega 1}}+{{v}_{\omega 2}})}\,\,and\,\,w=u\,({{v}_{w\,l}}+{{v}_{w2}})\] \[=\frac{v_{r2}^{2}-v_{r1}^{2}}{2{{R}_{d}}}=\frac{{{232}^{2}}-{{132}^{2}}}{2\times 0.5}\] \[=36.4=36.3\,\,kW\]
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